X
RAYS
Introduction
v
X-Rays
is an electromagnetic radiation.
-
It was
discovered by Wilhelm Rontgen. {A German}. He was conducting a research on
cathode rays.
v
X- Rays
owe their name to the fact that at the time of their discovery their nature was
unknown.
v X-rays
are now known that they are produced when fast moving electrons are suddenly
stopped by matter.
Production of x- rays
-
X-rays are produced in an x-ray tube.
This is when fast moving electrons suddenly hit a metal target.
-
When a current flows through the
filament, electrons are produced through thermionic emission.
-
Question using the kinetic
theory of matter explain how electrons are produced when cathode is heated.
-
The emitted/dislodged electrons are
accelerated towards the anode by the high potential difference of the order
100kv between the cathode and the anode.
-
The cathode is concave in shape
so as to focus the electron beam on to the target.
-
The target is usually made of tungsten/molybdenum
embedded onto copper. The
copper is a good conductor of heat that facilitates efficient
dissipation of heat.
-
Tungsten
has a high melting point .This makes it or (molybdenum) to withstand high
temperatures.
-
Most of the kinetic energy possessed by
the fast moving electrons is converted to heat (99.5%). Only 0.5 % is converted
to x-rays.
-
Cooling
in the tube if further enhanced by the cooling fins outside the tube and
the circulating oil.
-
The recent x-rays are made of a rotating
anode to change the point of impact with electrons. This reduces the
wear and tear on it.
-
The tube is made of a strong glass which
is highly evacuated. This ensures that the electrons do not loose
energy as they interact/collide with the air particles.
-
The target is set at an angle (i.e. 45°)
to the electron beam to direct the x-rays out of the tube through an opening on
the lead shield.
-
The off- focus (stray) x-rays are
normally absorbed by the lead shield.
-
The step up transformer provides the
high potential difference (high voltage).
-
NB: 1. during the half cycle when the
anode is positive with respect to the cathode, the produced electrons produce
x-rays when bombardment takes place at the target.
-
2. During the reverse half cycle, the
anode is negative with respect to the cathode. Electrons do not move to the
target and hence no bombardment takes place.
X-rays are not therefore produced in the reverse half cycle.
-
The production of x-rays only takes
place during the half cycle when the anode is positive with respect to the
cathode. But due to the high frequency of the a.c., production of x-rays
appears to be continues.
DIAGRAMS ---X-RAYS
Figure 1.1
Focusing Cup
• The focusing cup helps control
electron cloud. The electrons repel each other & want to spread out. The focusing
cup forces the electrons to form a small stream as they move toward the target
material.
–Made of nickel
– Has a low negative charge
Figure 1.2
Rotating Anode Assembly
Figure 1.3
Properties of x-rays
1.
They are neither deflected by the
magnetic or electric field. They are not therefore charged.
2.
They penetrate matter with the least
amount of penetration occurring in substances with the highest density e.g.
lead.
3.
X-rays affect photographic emulsions.
This property is used in x-ray photography.
4.
When moving through air, they knock off
electrons of molecules on their path. They therefore ionize the air molecules
increasing the electrical conductivity of the gases.
5.
They cause photoelectric emission.
6.
They cause fluorescence in certain
substances e.g. zinc sulphide.
7.
They are electromagnetic radiations of
shorter wavelength than the visible light. They can be plane-polarized and are
diffracted. They are therefore waves in nature.
8.
They travel in straight lines at the
speed of light (3.0 x 108 m/s).
PAST KCSE
QUESTIONS ON THE TOPIC X-RAYS
1. An X-ray tube is operating with an anode
potential of 10kV and a current of 15.0 mA.
a) Explain
how the
i) Intensity of X-rays from such a tube
may be increased.
ii) Penetrating power of X- rays from such
a tube may be increased
b) Calculate
the number of electrons hitting the anode per second.
c) Determine
the velocity with which the electrons strike the target.
d) State
one industrial use of X-rays.
2. a) For
a given source of X-rays, how would the following be controlled.
i) Intensity
ii) The
penetrating power
iii) The
exposure to patients
b) An accelerating potential of 20kv is
applied to an X-ray tube.
i) What is the velocity with which the electron
strikes the target?
ii) State the energy changes that take place at
the target.
3. Explain why X-rays are appropriate in study
of the crystalline structure materials.
4. Name the
metal used to shield X-rays operators from the radiation. Give reasons why it
is used.
5. State the properties of X-rays, which makes
it possible to detect cracks in bones.
6. State one
difference between hard X-rays and soft X-rays. (1mk)
7. A target was bombarded by electron
accelerated by a voltage of 106 V.
If all the K.E of the electrons was converted to X-rays, calculate:-
a) The
K.E of the electrons
b) The
frequency of the photons emitted.
8. An X-rays tubes gives photons of 5.9 x 10-15
J of energy. Calculate:-
a) The
wavelength of the photons.
b) The
accelerating voltage
c) The
velocity of the electrons hitting the target.
9. If accelerating voltage in an X-ray tube is
40kV, determine the minimum wavelength of the emitted X-rays. (Electronic charge = -1.6 x 10-19C,
planks constant = 6.6 x 10 -34Js, velocity of electromagnetic waves
= 3.0 x 108ms-1)
10. State the purpose of cooling fins in the X-ray
tube.
11. X-rays are produced by a tube operating at 1 x
104V. Calculate their wavelength. (Take h= 6.6 x 10 -34 Js, e= 1.6 x
10-19C, c= 3x108ms-1)
12. State and explain the effect of increasing the
EHT in an X- ray tube on the X-rays produced.
Answers
X-RAYS
1.
2.
(a) (i)
Heater current or Filament current
(ii) Anode Potential or operating potential
(iii) Covering with protective materials where
X- rays are not required
o
Minimize
exposure time as much as possible
o
Reduce
no of exposures as much as possible
(b) (i) ½
MeV2 = eV
V= √ (2eV)
Me
= √ 2 x 1.76 x
109 x 20 x 103
= 6.39 x 107
m/s
(ii) KE- Heat or internal energy and energy of
x- rays or radiation.
3.
X- Rays have wavelengths of the order
of the lattice spacing; and therefore they can be diffracted; (Diffraction due
to short wavelengths of x- rays). In calculation the atomic separation is equal
to slit separation- or grating separation. Lead because it is very dense, has
high atomic mass.
4.
(a) (i)
Increase the filament current
(ii) Increase the anode potential
(b)
Q= it = 15 x 10-3 A x is
= 15 x 10-3C
Electron
charge = 1.6 x 10-19 C
No.
of electrons in 15 x 10-3C
=
15 x 10-3 = 9.38 x 1016 e/s
1.6
x 10-19
(c)
½ mv2 = ev
V=
√ 2eV
Me
(2
x 1.6 x 10-19 x 10 x 103) ½
9.1
x 10-31
= 5.9 x 107
m/s
(d) - Detecting flows/ fault in metals or
other structures
-
Quality control of manufactured
items e.g. tyres, thickness of sheets,
Paper.
-
Analysis of gem stones
5.
Highly penetrating in matter
6.
Hard X- rays are more penetrating
than soft X- rays due to their higher frequency.
7.
(a)
1.6 x 10-13
(b) 2.424 x 1020Hz
8.
(a)
3.35 x 10-11m
(b) 36,875V
(c) 1.3 x 1016 m/s
9.
3.1
x 10-11m.
10.
The
fins are used to cool the copper rod which conducts heat away from the target
when electrons hit the target
11.
K.E
on input = e.v
= 1.6 x 10-19
C x 1 x 104V
= 1.6 x 10 – 15
Houles
Energy of x-
rays is hf
Where f= c
λ mm
hc = 1.6 x 10-15 Joules
λ mm
λ mm = 6.6 x 10-34 x 3 x 108
1.6 x 10-15
λ
mm = 1.24 x 10-10m
12.
Hard
x- rays produced higher EHT results in faster electrons hence higher energy x-
rays.
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